5/1/19 prisms/cylinder/pyramid/cones

This week we learned about prism , cylinders, pyramids, and cones. The surface area (S) of the right prism is S=L+2B, where L is its lateral area and B is the area of the base. A prism is a figure that has equal sides with a parallelogram. The formula for the prism would be S=Ph+2B, where h is the height. The surface area S of a right cylinder is S=2(pi)rh+2(pi)r^2, where r is the radius of the base. A cylinders is a 3D figure of a circlse which you have to find the are of. The surface area of S of a regular pyramid is S=1/2PL+B, where P is the perimeter of the base, L is the slant height and B  is the area of the base. A pyramid is shaped like an triangular Egyptian monument.  The surface area S is a right circular cone is S=(pi)rl+(pi)r^2, where r is the radius of the base and l is the slant height. A cone is shaped like a area, cone flipped upside down. The easiest one to solve is the pyramid and the hardest one to solve is the cone.

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